Study the given Venn diagram and answer the following questions.
List the elements of sets \(A\) and \(B\) in listing method.[1]
Write the improper subset of set \(B\).[1]
If set \(A\) contains only the element ‘\(r\)’, then what type of set relation exists between \(A\) and \(B\)? Give a reason.[1]
From the Venn diagram: \( A = \{p, q, r\} \) \( B = \{r, s, t\} \)
The improper subset of set \(B\) is the set \(B\) itself: \( \{r, s, t\} \)
If set \(A\) contains only the element \(r\), then \(A = \{r\}\) and \(B = \{r, s, t\}\).
In this case, \(A\) is a proper subset of \(B\) because every element of \(A\) is in \(B\)
Anisha bought a scooter for Rs 300000 and sold it to Divya after \(2\) years, deducting \(20\%\) of the price. Divya sold it to Gauri at a profit of Rs 6000.
Find the selling price of Anisha.[1]
Compare the price of Anisha and Gauri of the scooter in the ratio form.[2]
Selling price of Anisha:
Cost Price for Anisha = Rs. \(300,000\)
She sold it after deducting \(20\%\) of the price (i.e., a \(20\%\) depreciation or loss):
Thus Selling Price = 80% of 300,000= \(\dfrac{80}{100} \times 300,000 = 240,000\)
So, Anisha sold the scooter to Divya for Rs. 240,000.
Price comparison between Anisha (original buyer) and Gauri (final buyer):
Anisha’s purchase price = Rs. \(300,000\)
Divya’s purchase price = Rs. \(240,000\)
Next
Divya sold it to Gauri at a profit of Rs. 6,000, so Gauri’s purchase price = \(240,000 + 6,000 = 246,000\)
Now, ratio of Anisha’s price to Gauri’s price is \(300,000 : 246,000\)
or\(50 : 41\)
So, the ratio is \(50 : 41\).
Ganesh borrowed a sum of Rs 27,000 from his friend Bishnu. He paid an interest of Rs 5,400 to Bishnu at the end of 2 years.
Write the formula to find the rate of interest.[1]
Find the rate of interest at which Ganesh borrowed the sum.[1]
At the same rate of interest, calculate the interest for 3 years.[2]
If Ganesh had not paid any interest till the end of 3 years, how much amount would be needed to clear the loan?[2]
Formula to find the rate of interest: Rate (R) = \( \dfrac{I \times 100}{P \times T} \)
Rate of interest:
Principal (P) = Rs. 27,000
Time (T) = 2 years
Interest (I) = Rs. 5,400
Thus, Rate (R) = \( \dfrac{5,400 \times 100}{27,000 \times 2} = 10\% \)
So, the rate of interest is 10% per annum.
Interest for 3 years:
Time (T) = 3 years
Rate (R) = 10%
Thus, Interest (I) = \( \dfrac{27,000 \times 3 \times 10}{100} = 8,100 \)
So, the interest for 3 years is Rs. 8,100.
Amount to clear loan after 3 years:
Principal (P) = Rs. 27,000
Interest for 3 years (I) = Rs. 8,100
Thus, Amount (A) = P + I = 27,000 + 8,100 = 35,100
So, Rs. 35,100 would be needed to clear the loan.
The road between Rampur to Gaidakot is \(95\) kilometers.
Write the distance in scientific notation in meters.[1]
If Utsab drives his bike at the rate of \(19\,\text{km/hr}\), calculate the time taken to travel from Rampur to Gaidakot.[1]
Write \(35\) in the quinary number system.[1]
The monthly salary of Prakash is \(\text{Rs.}\,43{,}689\). Find his expenditure and saving amount if their ratio is \(2:1\).[2]
In the adjoining figure, LOVE is a square park. Inside that park, there is a circular pond. The side of the square is 25 m and the diameter of the pond is 14 m.
Write the formula to find the area of a circle. [1]
Find the area of the circular pond. [1]
Find the area of the park including the pond. [1]
How much does it cost to fence the park at the rate of Rs 650 per meter? [1]
Area of circle formula
We know that, Area (\( A \)) = \( \pi r^2 \)
Area of the circular pond
Given that, Diameter of pond (\( d \)) = 14 m
Therefore, Radius (\( r \)) = \( \frac{14}{2} = 7 \) m
Now using the formula, we get Area of pond (\( A_p \)) = \( \pi r^2 = \frac{22}{7} \times 7^2 = 154 \) m²
Area of the park including the pond
Given that the park is square, Side (\( l \)) = 25 m
Therefore, Area of park (\( A \)) = \( l^2 = 25^2 = 625 \) m²
(Note: Since the pond is inside the park, the total area including the pond is 625 m².)
Cost of fencing the park
We know that, Perimeter of square (\( P \)) = \( 4l = 4 \times 25 = 100 \) m
According to the question, the rate is Rs 650 per meter, so Total Cost = \( 100 \times 650 = \) Rs 65,000
What is the value of \(\left(\dfrac{3x}{y}\right)^0\)?[1]
Two equations are given below: \(x + 3y = 8\) and \(2x + y = 6\).
What is this system of equations called?[1]
Solve the above equations using a graph.[2]
Find the H.C.F. of \(x^2 - 5x + 6\) and \(x^2 - 4\).[2]
At what value of \(x\) does the expression \(x^2 - 7x - 18\) become zero?[2]
In the figure, \(PQ \parallel RS\). \(TR\) and \(TU\) are two transversals. If \(\angle PTR = 60^\circ\) and \(\angle QTU = 70^\circ\),
Find the values of \(x^\circ\) and \(y^\circ\).[2]
Experimentally verify that the angles of an equilateral triangle are equal. (Two different triangles are necessary.)[3]
By which axiom are the given triangles \(\triangle ABC\) and \(\triangle PQR\) congruent?[1]
Construct a parallelogram \(ABCD\) in which \(AB = 6cm\), \(AD = 5cm\), and \(\angle BAC = 60^\circ\).[3]
How can the area of the parallelogram be found? Write your argument.[1]
The vertices of \(\triangle ABC\) are \(A(3,2)\), \(B(5,6)\), and \(C(7,2)\).
How many triangular surfaces are there in a tetrahedron?[1]
In \(\triangle ABC\), if the bearing of point \(C\) from \(A\) is \(090^\circ\), find the bearing of \(A\) from point \(C\). Also, find the distance between points \(A\) and \(B\).[2]
Plot \(\triangle ABC\) on a graph and find the coordinates of the image of \(\triangle ABC\) after reflection in the \(x\)-axis. Also, plot its image on the same graph.[2]
The numbers of students in classes \(1\) to \(5\) in a school are given below. Study the table and answer the following questions:
Class
1
2
3
4
5
No. of students
\(12\)
\(18\)
\(15\)
\(25\)
\(20\)
What is the average number of students per class?[1]
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